The town librarian bought a combination of new-release movies on dvd for $20 and classic movies on dvd for $8. let x represent the number of new releases, and let y represent the number of classics. if the librarian had a budget of $500 and wanted to purchase as many dvds as possible, which values of x and y could represent the number of new-release and classic movies bought? x = 8, y = 45 x = 10, y = 22 x = 16, y = 22 x = 18, y = 18

Explanation:

1) Cost of x new release movies on DVD:

2) Cost of y classic movies on DVD:

3) Total cost of x new release and y classic movies on DVD:

4) Constrain:

5) Calculate the value of the left side of the inequality for the given pairs:

      x       y      20x + 8y

1) 8       45     20 (8) + 8 (45) = 160 + 360 = 520

 Since the total cost of this option is greater than $500, this is not valid.

2) 10        22   20(10) + 8(22) = 200 + 176 = 376

3) 16       22     20(16) + 8(22) = 320 + 176 = 496

4) 18        18       20(18) + 8(18) = 360 + 144 = 504

   (greater than the budget)

Thus, there are two valid options for which you must calculate the number of DVDs:

Conclusion: the number of new release and classic movies are x = 16 abd y = 22, for a total of 38 DVDs.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25