two airplanes leave the airport. plane a departs at a 44 angle from the runway, and plane b departs at a 40' from the runway. which plane was farther away from
the airport when it was 6 miles from the ground? round the solutions to the nearest hundredth
a. plane a because it has 8.64 miles away
b. plane a because it has 8.34 miles away
c. plane b because it was 7.83 miles away
d. plane b because it was 9.33 miles away

Option D

Plane B because it was 9.33 miles away

Step-by-step explanation:

This problem can be simulated by two right triangles:

For Plane A, we have the elevation angle . We know that the height is 6 miles.

To find the horizontal distance we use the function

By definition:

In this case:

hypotenuse=distance from the airport

Then:

distance from the airport: 8.64 miles

For Plane B, we have the elevation angle . We know that the height is 6 miles.

To find the distance we use the function

By definition:

In this case:

Hypotenuse=distance from the airport

Then:

distance from the airport: 9.33 miles

Finally the answer is the option D.

0 is its x and y coordinate

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!