Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? check all that apply.
–5
negative nine-halves
negative one-quarter
1
startfraction 9 over 4 endfraction

-5

negative nine-halves

Step-by-step explanation:

we know that

In the quadratic equation

If

then

The system has no real numbers solutions

we have

so

substitute

Verify each case

case 1) -5

For c=-5

substitute

------> is true

therefore

The value of c=-5 will cause the quadratic equation  to have no real number solutions

case 2) negative nine-halves

For c=-9/2

substitute

------> is true

therefore

The value of c=-9/2 will cause the quadratic equation  to have no real number solutions

case 3) negative one-quarter

For c=-1/4

substitute

------> is not true

therefore

The value of c=-1/4 will not cause the quadratic equation  to have no real number solutions

case 4) 1

For c=1

substitute

------> is not true

therefore

The value of c=1 will not cause the quadratic equation  to have no real number solutions

case 5) 9 Over 4

For c=9/4

substitute

------> is not true

therefore

The value of c=9/4 will not cause the quadratic equation  to have no real number solutions

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