In baseball, the pitcher's mound is 60.5 feet from home plate. if the fastest pitch ever recorded in major league baseball was 105.1 miles per hour, how many seconds did it take for the ball to travel from the pitcher's mound to home plate? round the answer to the nearest tenth.

t=0.4 sec

Step-by-step explanation:

Remember that

1 mile=5,280 feet

1 hour=3,600 seconds

Let

s > the speed in ft/sec

d > the distance in ft

t > the time in sec

s=d/t

Solve for t

t=d/s

step 1

Convert  miles/hour to ft/sec

105.1 mi/h=105.1(5,280/3,600)=154.15 ft/sec

step 2

Find the time

t=d/s

we have

s=154.15 ft/sec

d=60.5 ft

substitute

t=60.5/154.15

t=0.4 sec

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)