Aa, b bb, and c cc are collinear, and b bb is between a aa and c cc. the ratio of a b aba, b to b c bcb, c is 3 : 1 3: 13, colon, 1. if a aa is at ( − 7 , 3 ) (−7,3)left parenthesis, minus, 7, comma, 3, right parenthesis and b bb is at ( − 1 , 0 ) (−1,0)left parenthesis, minus, 1, comma, 0, right parenthesis, what are the coordinates of point c cc?

  C = (1, -1)

Step-by-step explanation:

For that 3:1 division, the calculated value of point B is ...

  B = (3C +1A)/(3+1)

Solving for the value of C, we find ...

  4B = 3C + A . . . . multiply by 4

  4B -A = 3C . . . . . subtract A; next divide by 3.

  C = (4B -A)/3 = ((4(-1)-(-7))/3, (4(0)+-3)/3) . . . . substitute given values

  C = (3/3, -3/3) . . . . simplify a bit

  C = (1, -1)

answer: 20

step-by-step explanation: