Find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16 cm and 30 cm.

Hi there, A=1/2(b1+b2)=1/2(h)(30+16). What we have to do is find h, 30-16=14/2=7, 25²-7²=625-49=576, we know that 576=24. So, h=24, 1/2(24)(30+16)=12(46). So, the area is 552 cm². Now, it's time to find the perimeter. P=b+b+l+l=30+16+25+25=96 cm. Therefore, the area is 552 cm² and the perimeter is 96 cm.