Acrane lifts a pallet of concrete blocks 8 feet from the back of a truck. the truck drives away and the crane lowers the pallet 13 feet. what is the final position of the pallet relative to where it started in the back of the truck?

The final position is 5 feet below the back of the truck

Step-by-step explanation:

* Lets explain how to solve the problem

- A crane lifts a pallet of concrete blocks 8 feet from the back of

 a truck

- The crane lowers the pallet 13 feet after the truck drives away

- Assume that the zero level of the position of the ballet of concrete

 blocks is the back of the truck

∵ The crane lifts the pallet of concrete blocks 8 feet from the back

  of the truck

- That means it take the pallet from zero to 8

∴ The height of the pallet of concrete blocks is 8 feet over

   the starting position

∵ The crane lowers the pallet of concrete blocks 13 feet

- That means the crane lower the pallet from the height 8 and

  lift it down 13 feet, so we must to take out from the 8 feet the

  13 feet to find the final position of the pallet of concrete blocks

∴ The pallet position is ⇒ 8 - 13 = -5

∴ The position of the pallet of concrete blocks is 5 feet below the

   starting position which is the back of the truck

* The final position is 5 feet below the back of the truck

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

0.32

step-by-step explanation:

2.24/7