Will give brainliest
(this is a long answer)
if trapezoid jklm is reflected over the x-axis, what do you notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis?

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M  , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however  the y coordinates remains the same.

The coordinates will be as shown in the image attached.

Original: M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).Reflected: M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).

Step-by-step explanation:

The coordinates of the given trapezoid JKLM are

M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).

If we want to reflect the trapezoid JKLM over the x-axis, we just need to change its vertical coordinates for their opposite, that is

M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).

There reason of this is because if we need a reflection across x-axis, what changes is vertical coordintes, because the figure must go from I quadrant to IV quadrant where y-valus are negative, and x-values remains positive.

Therefore, the ordered pair of the original figure are:

M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).

The ordered pair of the reflection are:

M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.

7.3

step-by-step explanation:

81+30=111180 minus 111=691/2×19=9.569÷9.5=7.263157895~7.3