Find the equation of the line in standard form for the given slope and point
1.(3,1) m=-3
2.(0,-4) m= 1/2

1. y - 1= -3(x-3)

y - 1 = -3x + 9

y= -3x + 10

3x + y = 10

2. y + 4 = 1/2(x - 0)

y + 4 = 1/2x - 0

y = (1/2)x - 4

-x + 2y = -8

Step-by-step explanation:

2. y + 4 = ½(x)

y + 4 = ½x

- 4- 4

y = ½x - 4 [Slope-Intercept Form]↷

-½x - ½x

-2[-½x + y = -4] [We do not want denominators in our equation, so multiply by -2 to get rid of it.] ↓

x - 2y = 8 [Simplified in Standard Form]

1. y - 1 = -3(x - 3)

y - 1 = -3x + 9

+ 1+ 1

y = -3x + 10 [Slope-Intercept Form]

+ 3x +3x

3x + y = 10 [Standard Form]

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