The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. refer to exhibit 6-2. what percent of players weigh between 180 and 220 pounds?
a. 0.5762%
b. 57.62%
c. 28.81%
d. 0.281%

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

i need more details sorry

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.