Abarge is pulled by two tugboats as shown in the figure below. to move the barge along in the water properly, the tugboats must exert a result force of 10,000 lbs along the direction of motion of the barge. (1) determine the tension in each rope if the position of tug b is such that 8-45 degrees. (2) suppose that tug b can move anywhere such that 0 ? 90 degrees, determine the angle ? at which the angle in the tug b's rope is maximum, and again, at which the tension has minimum value, still maintaining the resultant of 10,000 lbs along the x- direction. 2. it loop)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

ome people is not even worth it to even try it in the air.

step-by-step explanation: