Anewspaper conducted a statewide survey concerning the 1998 race for state senator. the newspaper took a srs of n=1000 registered voters and found that 520 would vote for the republican candidate. let p represent the proportion of registered voters in the state who would vote for the republican candidate. we test h0: p=.50 ha: p> .50 (a) what is the z-statistic for this test? 32856.06 (b) what is the p-value of the test? 0

(a) The z-statistic for this test is 1.265.

(b) The P-Value is 0.102936.

Step-by-step explanation:

Given information:

n=1000

Republican candidate = 520

Sample proportion p =

H0 : p=0.50

Ha : p>0.50

It is right tailed test.

Hypothesized proportion = 0.5

Assumed that the data is normally distributed.

(a)  The z-statistic for this test is

where, p is sample proportion .

P is hypothesized proportion.

Q = 1-P

n is sample size.

The z-statistic for this test is

Therefore the z-statistic for this test is 1.265.

(b)

Level of significance is not given so let as consider α =0.05.

The P-Value for right tailed test at significance level α =0.05 is 0.102936.

Therefore P-Value is 0.102936.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer: it is d

step-by-step explanation: