Find the length of segments ab and bc.

AB = 10

BC = 48

Step-by-step explanation:

Assuming ABC is a straight line,

then AC = AB + BC

It is given that :

AB = x - 5

BC = 3x + 3

AC = 6x - 32

hence

AC = AB + BC

or

(6x - 32) = (x - 5) + (3x + 3)

6x - 32 = x - 5 + 3x + 3

6x - 32 = 4x - 2

6x - 4x = -2 + 32

2x = 30

x = 15

hence

AB = x - 5 = 15 - 5 = 10

BC = 3x + 3 = 3(15) + 3 = 48

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: