In a library, bookcases a, b,c and d are lined up in order. bookcase a is 1.38 meters from bookcase b and 6.8 meters from bookcase c. bookcase d is 0.925 meters farther from bookcase c than the distance between bookcases b and c. how far apart are bookcases c and d? (show your work).

Bookcases C and D are 6.345 meters apart

Explanation:

The given scenario can be modeled using the attached diagram

Assume that the distance between cases B and C is x meters

We are given that:

Distance between cases A and B is 1.38 m

Distance between cases A and C is 6.8 m

We know that:

Distance between A & C = Distance between A & B + Distance between  B & C

This means that:

6.8 = 1.38 + x

x = 6.8 - 1.38 = 5.42 m

Now, we are given that bookcase D is 0.925 meters farther from bookcase C than the distance between bookcases B and C

This means that:

Distance between cases C & D = Distance between cases B & C + 0.925

Distance between cases C & D = x + 0.925

Distance between cases C & D = 5.42 + 0.925

Distance between cases C & D = 6.345 meters

Hope this helps :)

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step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for