Multiple binomials by polynomials problem (2+3w)(w^2+6w+9)

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w)(w² + 6w + 9)

To find the multiplication

(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9

 = 2w² + 12w + 18 + 3w³ + 18w²  + 27w

 = 3w³ + 20w² + 39w + 18

Therefore the final value =  3w³ + 20w² + 39w + 18

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

207/8 is the right