Rosencrantz chooses a coin from guildenstern's collection of one hundred pennies and promptly tosses six heads in a row. while rhapsodizing over his good luck, he learns that four of the pennies were two-headed. the probability that rosencrantz chose one of the two-headed pennies given that he flipped six heads in a row can be expressed in the form m/n, where m and n are relatively prime positive integers. find m, n.

it can be to see completed examples before writing, in order to examine what makes for an effective piece. see how these intros give some context before posing the topic and lead naturally into the body paragraphs, where the evidence will be listed. you can imagine how the author has organized the rest of the piece.

"we buried my cousin last summer. he was 32 when he hanged himself from a closet coat rack in the throes of alcoholism, the fourth of my blood relatives to die prematurely from this deadly disease. if america issued drinking licenses, those four men—including my father, who died at 54 of liver failure—might be alive today. that is a good example piece   some steps that are .

. writing something that happened to you

.read a book you like to get ideas from there

. lastly you can make a venn diagram

hope this plz make brainliest

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

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