Xand y work at constant rates. how many more hours does it take machine y, alone, to fill an order of a certain size than machine x alone? i. x and y together fill order in 2⁄3 the time that x alone does. ii. y alone does it in twice the time as x alone does.

Answer with explanation:

V=Volume of tank

It is given that, X and Y work at constant rates.

Let rate of doing work of X is x  hour.

And, Rate of Doing work of Y is y  hour.

Statement I----X and Y together fill order in 2⁄3 the time that X alone does.

                                         -------------------------------------------------(1)

Statement II----Y alone does it in twice the time as X alone does.

Substituting the value of y in 1

→x≠ -2, because Rate of doing work can't be negative.

Substituting the value of x in 1, gives

→Rate of doing work of X= 2 hour

→Rate of doing work of Y=1 hour

i'm not sure i quite understand, could you provide more information?

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2