An arithmetic sequence is defined by the recursive formula t1 = 44, tn + 1 = tn + 16, where n ∈n and n ≥ 1. which is the general term of the sequence? a) tn = 44 + (n - 1)16, where n ∈n and n ≥ 1 b) tn = 44 + (n + 1)16, where n ∈n and n ≥ 1 c) tn = 44 + (n - 2)16, where n ∈n and n ≥ 1 d) tn + 1 = 44 + (n - 1)16, where n ∈n and n ≥ 0

According to this rule, we get

and so on, up to

Then

which matches answer A.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~