Match each quadratic function given in factored form
with its equivalent standard form listed on the left.
f(x) = (x + 2)(x – 6)
f(x) = (x – 4)(x+3)
f(x) = (x – 12)(x+1)
f(x) = (x – 3)(x +4)

(x+2)(x-6)=x^2 - 4x -12

(x-4)(x+3)=x^2 - x - 12

(x-12)(x+1)=x^2 - 11x - 12

(x-3)(x+4)=x^2 + x - 12

Step-by-step explanation:

You do the calculations:

(x + a) (x + b) = x^2 +ax + bx + ab = x^2 + (a+b) + ab, where a and b are real numbers. (At least in this case)

answer: idk

step-by-step explanation: sry idk

ljn

step-by-step explanation: