1) find an equation in standard form for the hyperbola with vertices at (0, ±2) and foci at (0, ±11).
2) find an equation in standard form for the hyperbola with vertices at (0, ±2) and foci at (0, ±11).
3)eliminate the parameter.
x = t - 3, y equals two divided by quantity t plus five
4)the height of the tunnel at the center is 58 ft, and the vertical clearance must be 29 ft at a point 21 ft from the center. find an equation for the ellipse.
5)determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
r = 4 cos 5θ

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

you answer is a

step-by-step explanation:

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: