If dy/dx = x^2 + 4 what is the value of y

  y = (1/3)x^3 +4x + c . . . . . for some constant c

Step-by-step explanation:

The anti-derivative of x^n is (x^(n+1))/(n+1). Applying this rule to each of the terms in dy/dx, we get ...

  y = (1/3)x^3 + 4x

There may be an added constant as well, conventionally represented by "c".

  y = (1/3)x^3 +4x +c

1; 35 is the ratio

step-by-step explanation:

answer is x<