What values are solutions of 0 =2xexponent of 2 -6x-8

x = -1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0it gives you the two brackets of(2x-8)(x+1)=0

then...you equate the two brackets to 0.separately

2x-8 = 0which gives you...x = 4...as the first solution..then..;

x+1 = 0which gives you...x = -1...as the second solution

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.