Identify the equation of the circle that has its center at (-16,30) and passes through the origin

(x+16)²+(y-30)²=1156

Step-by-step explanation:

We have given:

center at (-16,30). It means h = -16 and k=30

and it passes through the origin (0,0)

Thus the  radius will be distance between (-16,30) and (0,0)

r=√(-16 - 0)²+(30-0)²

r=√256+900

r²=(√1156)²

r²=1156

Now apply standard equation of circle:

(x-h)²+(y-k)² = r²

(x+16)²+(y-30)²=1156

Thus the equation is (x+16)²+(y-30)²=1156

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation: