B. from where the shoes spilled (48°n, 161°w) to where they were found on may 22nd 1996 (54°n, 133°w), how many kilometers did they travel? how many days did they take to travel that distance (use april 30 as the date found)? what was their rate of travel in kilometers per hour?

To find kilometers using latitude and longitude:

distlon = lon2 - lon1   = 133-161 = -23

distlat = lat2 - lat1  = 54-48 = 6

a = (sin(distlat/2))^2 + cos(lat1) * cos(lat2) * (sin(distlon/2))^2  

a = (sin(6/2)^2 + cos(48)*cos(54)* sin(-23/2)^2

c = 2 * arctan2( sqroot(a), sqroot(1-a) )  

d = R * c (where R is the radius of the Earth, 6373 km's)

d = 2052 km's

April 30th to May 22nd is 23 days.

23 days x 24 hours per day = 552 hours.

Rate of travel = 2052 / 552 = 3.717 km per hour ( round answer as needed.)

he answer is x=1x3 because x=1 to x=3

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.