Atriangle was dilated by a scale factor of 2. if cos a° = three fifths and segment fd measures 6 units, how long is segment de?
triangle def in which angle f is a right angle, angle d measures a degrees, and angle e measures b degrees
segment de = 3.6 units
segment de = 8 units
segment de = 10 units
segment de = 12.4 units

10 units

Step-by-step explanation:

The cos --> adjacent/ hypotenuse.

cos--> 3/5

FD is the adjacent which is 3

DF is the Hypotenuse which is 5

It then states it was dilated by a scale factor of 2, and ask for segment DE

You then take the Hypotenuse ( 5 ), and multiply it by 2 and it then equals 10.

Hope this helped sorry if i'm late. :)

Looking for brainliest answers if you can give pls, thx.

10 units

Step-by-step explanation:

Soh Cah Toa is a acronym used in trigonometry classes to help remember the right-triangle definitions for sine, cosine, and tangent.

We are really wanting to use the Cah part since we are given cos(a)=3/5.

So I know my adjacent side measurement to angle a is going to be of the form 3m and the hypotenuse measurement is going to 5m.

They later say angle D was the one that had measurement a degrees.  So I knew FD will be in the form 3k and ED would be in the form of 5k.

We are given FD is also 6.  

So 3k=6 units means k=2.  We were told we had a dilation of 2.  The triangle we dilated from originally had a measurement of 3 units there.

So we are looking for the measurement of ED which is 5k where k is 2. So ED has measurement 5(2)=10 units.

this is a very good question

step-by-step explanation:

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f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!