Astudy of lobster trap placement used a 90% confidence interval to estimate the mean trap spacing (in meters) for the population of red spiny lobster fishermen fishing in the west coast. how many teams of fisherman would need to be sampled in order to reduce the width of the confidence interval to 6 meters? assume prior knowledge indicates that the trap spacing readings for the population of red spiny lobster taken during a day are approximately normally distributed with a standard deviation of 11.9 meters.'\

Step-by-step explanation:

Given that a study of lobster trap placement used a 90% confidence interval to estimate the mean trap spacing (in meters) for the population of red spiny lobster fishermen fishing in the west coast.

Margin of error = 3 metres (half of width of confidence interval)

STd deviation = 11.9 metres

For 90% confidence interval we have margin of error

=

n =10.644

=11

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)