In this problem, we study a simple noisy communication channel. suppose that x is a binary signal that takes value −1 and 1 with equal probability. this signal x is sent through a noisy communication channel, and the medium of transmission adds an independent noise term. more precisely, the received signal is y=x+n, where n is standard normal, indpendendent of x. the decoder receives the value y of y, and decides whether x was 1 or −1, using the following decoding rule: it decides in favor of 1 if and only ifp(x=1|y=y)> 2p(x=−1|y=y) it turns out that the decoding rule can be expressed in the form: decide in favor of 1 if and only if y> t, for some threshold t. find the threshhold t. as an intermediate step, find p1≜p(x=1|y=y).p1=now find t. t=

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

a function could be identified in 3 ways either on a chart,graph, or ordered pairs. first a function is that each point has its own. the rule is that there can be many x's to one y but there can not be 2 x's at different y's. so on a graph when you put a straight line through the y's there should be one dot only to be a function.

step-by-step explanation:

1/800 is the right answer

answer: sherk

step-by-step explanation:

just give up and watch the best anime ever sherk