"a developer wants to enclose a rectangular grassy lot that borders a city street for parking. if the developer has 272 feet of fencing and does not fence in the side along the street, what is the largest area that can be enclosed? "

The largest area that can be enclosed is 9248 square feet.

Step-by-step explanation:

This is a typical problem of optimization that can be solved using derivatives. We have a rectangular region, and let us denote the height by , and the base by .

Then, the area of the rectangle is . Notice that the area is a function of and , but if we want to use calculus, we should have only one variable. This can be done if we find a relationship between both variables.

Recall that the fences will not bu used in the whole perimeter of the rectangular area, but only in three sides. Hence, . (Without lost of generality we can consider , instead.)

Then, ans substituting in the formula for the area:

Taking derivative with respect to x:

Its only zero can be found solving the equation . Hence, its only zero of is . In order to assure that 68 is a point of maximum, we find and conclude that, in effect, 68 is a point of maximum.

We obtain the value of substituting the value of in the relationship between both variables: . With the values of and we can calculate the desired area:

on friday there were 15 birds

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all