Which statement best describes why there is no real solution to the quadratic equation y = x2 - 6x + 13?
the value of (-6)2 - 4 • 1 • 13 is a perfect square.
the value of (-6)2 - 4 • 1 • 13 is equal to zero.
the value of (-6)2 - 4 • 1 • 13 is negative.
the value of (-6)2 - 4 • 1 • 13 is positive.

C.

Step-by-step explanation:

when compared to tells us:

.

The discriminant, tells how many real solutions we will have.

If is zero then you have one real solution.

If is positive then you have two real solutions.

If is negative then you have no real solutions.

Our discriminant is negative, so we have no real solutions.

The answer you are looking for is the one that says your discriminant is negative which is C.

Step-by-step explanation:

Next time, please share the possible answers.  Thanks.

Here the coefficients are a = 1, b = -6 and c = 13.  Let's calculate the determinant b^2 - 4ac:  d = (-6)^2 - 4(1)(13) ) = 36 -52 = -16.

Because the determinant is negative, this quadratic has only complex roots.  The third answer applies here.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation:

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: