Apollster would like to estimate the fraction p of people in a popu- lation who intend to vote for the particular candidate. how large must a random sample be in order to be at least 95% certain that the fraction ^p of the positive answers in the sample is within 0: 02 of the true p?

sample n is 2401

Step-by-step explanation:

given data

error E = 0.02

confidence level = 95%

to find out

sample n

solution

we know for 95% CONFIDENCE  level z value is 1.96

we will apply here margin of error formula i.e

E = Z  × √( p(1-p)/n

0.02= 1.96 × √( 0.5(0.5)/n

√n = 0.98 / 0.02

n = 2401

so sample n is 2401

-1/2 +2

step-by-step explanation:

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: