When a fair coin is flipped, the probability of its landing heads (h) is 0.500.50 and the probability of its landing tails (t) is also 0.500.50. make a list of all the possible arrangements for flipping a fair coin twice, using h for heads and t for tails. find the probabilities of each arrangement.

probability (HH) = 1/4 = 0.25

probability (HT) = 1/4 = 0.25

probability (TH) = 1/4 = 0.25

probability (TT) = 1/4 = 0.25

Step-by-step explanation:

given data

probability heads (H) is 0.50

probability heads (T) is 0.50

to find out

the probabilities of each arrangement

solution

when coin toss there are two outcome that is head or tail

and then flip 2 time

possibility are HH  HT TH  TT

so

probability (HH) = 1/4 = 0.25

probability (HT) = 1/4 = 0.25

probability (TH) = 1/4 = 0.25

probability (TT) = 1/4 = 0.25

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: