If x is a real number such that x3 = 64, the x2 + x equals what?

20

Step-by-step explanation:

Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to x = 4.

Plugging that into our expression gives us 4² + 4, which is 20.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

equal to

step-by-step explanation: