The coordinate of j' after a reflection of the triangle is about the line y= -x. the coordinates of j is (-2,-1)

The reflection line is located at y = -x

For point J, x is -2, so y = -(-2), which equals 2.

When it is a reflection across Y, the X values remain the same.

Find the distance of the Y point to the reflection line,

The distance from -1 to 2 is 3 units.

The new point needs to be the same distance from the reflection line.

2 +  3 units = 5.

Point J' would be (-2,5)

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

you cant answer this dummy

step-by-step explanation: