(5) 5x 6y 1 y-6x-7y + 1 (10) assume that the system: represents two competing populations, with ni being the desirable population and n2 a parasite. compute the populations ni (t) and n2(t) and any time t. show that both populations are headed for extinction. h ou that both populations ar

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

dude thats to long figure it

step-by-step explanation:

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~