Mathematics, 08.08.2019 00:30 BlackAfro17
Abody of mass 5 kg is projected vertically upward with an initial velocity 48 meters per second. the gravitational constant isg = 9.8m/s2. the air resistance is equal to k|v| where k is a constant find a formula for the velocity at any time ( in terms of k ): v(t) = find the limit of this velocity for a fixed time 10 as the air resistance coefficient k goes to (enter 10 as tzero .) v(10) = how does this compare with the solution to the equation for velocity when there is no air resistance? this illustrates an important fact, related to the fundamental theorem of ode and called 'continuous dependence' on parameters and initial conditions. what this means is that, for a fixed time, changing the initial conditions slightly, or changing the parameters slightly, only slightly changess the value at time t. the fact that the terminal time t under consideration is a fixed, finite number is important. if you consider 'infinite' t, or the 'final' result you may get very different answers. consider for example a solution to y' = y, whose initial condition is essentially zero, but which might vary a bit positive or negative. if the initial condition is positive the "final" result is plus infinity, but if the initial condition is negative the final condition is negative infinity
Answers: 3
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Mathematics, 21.06.2019 18:20
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Mathematics, 21.06.2019 23:30
Which shows the first equation written in slope-intercept form? 1/2 (2y + 10) = 7x
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Abody of mass 5 kg is projected vertically upward with an initial velocity 48 meters per second. the...
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