Set up an initial value problem that represents the situation (you do not need to solve it! ) a tank initially contains 200 l of water, into which 50 g of salt has been dissolved. a solution of 10 g/l of salt is flowing into the tank at 20 l/min, and the resulting mixed solution is flowing out at a rate of 25 1/min. how much salt will be in the tank at any time t, 0

18

step-by-step explanation:

ik this stuph and i am smart donkey

1/2*qr*rs

step-by-step explanation:

answer: 1 + 1 = 11

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!