Three friends went to the fair. michelle ate three hot dogs, one pretzel, and two snow cones. she spent $25. amanda ate two hot dogs, three pretzels, and three snow cones. she spent $30. lucas ate two hot dogs, two pretzels, and four snow cones. he spent $25. which system of equations matches the friends' night at the fair?
2x + y + 3z = 25
2x + 3y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
2x + 3y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
3x + 2y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
2x + 3y + 3z = 30
2x + 4y + 2z = 25

b.

Step-by-step explanation:

We are given that three friends went to fair

Let cost of hot dog=x

Cost of pretzel=y

Cost of snow cone=z

Michelle ate 3 hot dog,one pretzel and two snow cones and spent $25.

Therefore, according to question the equation is

Step-by-step explanation:

We are given that three friends went to fair

Let cost of hot dog=x

Cost of pretzel=y

Cost of snow cone=z

Michelle ate 3 hot dog,one pretzel and two snow cones and spent $25.

Therefore, according to question the equation is

Amanda ate two hot dog, three pretzel and three snow cones and spent $30Therefore,the equation is [tex]2x+3y+3z=$30" />

Lucas ate two hot dogs,two pretzel and four snow cones and spent $25.

Therefore, the equation is

Hence, option b is true.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.