Two fair six-sided dice are rolled. what is the probability that the sum of the numbers rolled is either 6 or 12? 136+136=236 536+112=29 536+136=16 16+136=736

Step-by-step explanation:

Two dices are rolled so total number of sample space =6×6=36

sample space

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (22) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The event which has sum 6,  (1,5) (2,4) (3,3) (4,2) (5,1)

So the required probability

The event which has sum 12 , (6,6)

So the required probability =    

So the total probability =

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

56

step-by-step explanation: