The perimeter of a triangle is 50yd. the longest side is twice the length of the shortest side, and the second side is two yards more than the shortest side. find the lengths of the sides

Longest side + second side + shortest side = 50
Longest side = 2(shortest side)
Second side = (shortest side) + 2
Shortest side = shortest side
**
[2(shortest side)] + [(shortest side)+2] + (shortest side) = 50
4(shortest side) + 2 = 50
(shortest side) = 12
**
Shortest side = 12
Second side = 12+2=14
Longest side = 2*12=24
12+14+24=50, woo hoo this answer works

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Ithink it’s d as the answer.