I’m really confused about these can anyone me with this?

Statement ∠BCA≅∠DAC  

Reason; SSS congruence

Step-by-step explanation:

Remember each pair of opposite sides of a parallelogram is congruent

Opposite sides are congruent  

AD=BC, AB=DC

Using corresponding parts of congruent triangles

∠ACD≅∠CAB  and

∠ADC≅∠CBA

Let AC be a transversal for AB and CA then ;

∠ACB ≅∠CAD   and ∠ACD≅∠CAB are alternate angles

From the theorem; two lines in a plane are parallel if and only if a pair of altenate interior angles formed by the transversal is congruent as proven above.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

i think it’s a i believe