If f(x) = 16x - 30 and g(x) = 14x - 6, for which value of x does (f-g)(x) = 0?
-18
0 -12
0 12
0 18

f(x) = 16x – 30 (Given)

g(x) = 14x – 6 (Given)

Find (f - g)(x) :

(f - g)(x) = f(x) - g(x)

(f - g)(x) = (16x – 30) - (14x – 6)

(f - g)(x) = 16x – 30 - 14x + 6

(f - g)(x) = 2x – 24

Solve x:

Given that (f - g)(x) = 0

2x – 24 = 0

2x = 24

x = 12

x = 12

x = 12

Step-by-step explanation:

note that f - g)(x) = f(x) - g(x), hence

16x - 30 - (14x - 6) = 0

16x - 30 - 14x + 6 = 0

2x - 24 = 0 ( add 24 to both sides )

2x = 24 ( divide both sides by 2 )

x = 12

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*