Input the equation of the given line in standard form.
the line with m= 2/3 and passing through (1, 1)

y = 2/3x + 1/3

Step-by-step explanation:

Standard form of a line looks like y=mx+b. We already know that m is 2/3, but we don't know b. b is our y-int. With the given information, we can write this equation is point-slope form. That looks like y - y1 = m(x-x1). (x1, y1) = (1, 1) - the point given to us. So if you plug in that point to the equation, and the slope - m, it'll look like y - 1 = 2/3 (x - 1).

From here, you can just solve for y, and it'll be in standard form. I would distribute 2/3 first.

y - 1 = 2/3x - 2/3

Then, add 1 to both sides.

y = 2/3x + 1/3

what? that isnt a question

step-by-step explanation: