Assume that when adults with smartphones are randomly selected, 57% use them in meetings or classes. if 9 adult smartphone users are randomly selected, find the probability that at least 3 of them use their smartphones in meetings or classes the probability is ?

0.9617

Step-by-step explanation:

Given : The proportion of adults use their phones in meetings or classes : p=0.57

Number of adults randomly selected : n= 9

Let x be the random variable that represents the number of adults use their phones in meetings or classes.

By using binomial probability formula, to find the probability of getting success in x trials.

The probability that at least 3 of them use their smartphones in meetings or classes will be :-

Hence, the required probability is 0.9617 .

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x