Aphysical fitness association is including the mile run in its secondary-school fitness test. the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and a standard deviation of 60 seconds. find the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds.

The probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107

Step-by-step explanation:

Consider the provided information.

It is given that mean is 440 seconds and standard deviation is 60 seconds.  

z factor for less than 302 seconds would be:  

z = (302 - 440) / 60 = -2.3

The probability of getting a z factor of less than -2.3 = 0.0107 approximately.  

looking up in the z-table for a z factor of -2.3.

The probability of a student running the mile in less then 302 seconds would be 0.0107.

Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107

6 and 24

step-by-step explanation:

6 x 4 = 24

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33