If a is the average (arithmetic mean) of 6m and 10, b is the average of 4m and 4, and c is the average of 14m and 16, what is the average of a, b, and c in terms of m?

6m+7.5

Step-by-step explanation:

the arithmetic mean is the average of two numbers

it is given that a is average of 6m and 10

so

b is the average of 4m and 4

so

c is the average of 14m and 16

so

now the average of a ,b and c is given by

y + 11 = (1/4)(x + 16)

step-by-step explanation:

susie has 7 apples