Ms. johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about acceleration due to gravity. the program reports a mean of 31.5 and a standard deviation of 2.5. what is the variance of the data? round to the nearest tenth. a. 2.5b. 5.6c. 1.6d. 6.3

d.6.3

Step-by-step explanation:

Given : Ms. Johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about acceleration due to gravity.

The program reports a mean and a standard deviation

We know that the variance is the square of the standard deviation.

So , the variance of the data will be :-

Hence, the variance of the data =6.3

6.3

Step-by-step explanation: sigma^2 (2.5^2) equals 2.5x2.5 = 6.3, so it would be 6.3.

step-by-step explanation:

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

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