What are the coordinates of y' after a dilation of 3/2 about the origin?
the coordinates are y(0,-2)

  Y'(0, -3)

Step-by-step explanation:

Dilation about the origin multiplies every coordinate.

Y' = (3/2)Y = (3/2)(0, -2) = (0·3/2, -2·3/2) = (0, -3)

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m