Use the quadratic formula to find the solutions to the equation. x^2-3x+1=0

x = [-b +- sq root (b^2 - 4 ac)] / 2a

a = 1 b = -3 c = 1

x = [- -3 +- sq root (9 - 4 * 1 * 1)] / 2 * 1

x = [3 +- sq root (5)] / 2

x1 = 1.5 + sq root (5) / 2

x2 = 1.5 - sq root (5) / 2

Step-by-step explanation:

For this case we have the following quadratic equation:

The solution is given by:

We have to:

Substituting:

We have two roots:

step-by-step explanation:

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