Worth lots of extra points + a friend if you answer
two stoves were turned off at the same time, and they both started to cool down.
the following equation gives the temperature of the first stove (in degrees celsius) as a function of time (in minutes)
t= 180 - 1.55m
the graph of the temperature of the second stove (in degrees celsius) as a function of time (in minutes) is shown below.
which stove started at a higher temperature?
a. first stove
b. second stove
c. the stove started at the same temperature
which stove cooled down at a greater rate?
a. first stove
b. second stove
c. the stoves cooled done at same rate

Which stove started at a higher temperature?

Second stove

Which stove cooled down at a greater rate?

First stove

Step-by-step explanation:

Which stove started at a higher temperature?

"Started" ---> x = 0

T= 180 - 1.55(0)

T = 180 °C

T = 200 °C

180 °C < 200 °C     ----->     32 °F < 392 °F

Which stove cooled down at a greater rate?

x = 40

slope (rate) = -1.55 °C/min

P1(0,200)     and   P2 (40,130)

-1.55 > -1.75

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: