Apackage delivery service claims that no more than 5 percent of all packages arrive at the address late. assuming that the conditions for the binomial hold, if a sample of size 10 packages is randomly selected and the 5 percent rate holds, what is the probability that more than 2 packages will be delivered late? round to four decimal places.

0.0115

Step-by-step explanation:

The binomial probability formula :-

, here n is the number total of trials , p is the probability of getting success in each trial and P(x) is the probability of getting success in x trial.

Given : A package delivery service claims that no more than 5 percent of all packages arrive at the address late.

We assume that the conditions for the binomial hold with parameters :-

n=10 ; p=0.05

Let x be the random variable that represents the number of packages arrive at the address late.

Now, the probability that more than 2 packages will be delivered late :-

Hence, the probability that more than 2 packages will be delivered late = 0.9885

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)

hi there!

the answer will be d: 2